Lesson 8 of 10
How to Find Change in Velocity: Why It's 7, Not 3
速度变化量
A ball hits the ground at 5 m/s and bounces up at 2 m/s. Is its change in velocity 3 m/s or 7 m/s?
Lesson notes
A short written version of Lesson 8. The study sheet has more practice questions.
Short answer
The change in velocity is 7 m/s, pointing up, not 3 m/s. Take down as the positive direction: v₀ = +5 m/s and vₜ = −2 m/s, so Δv = −2 − 5 = −7 m/s. The minus sign means up.
Key ideas
- Change = final − initial, never initial − final. Money from 3000 to 4000 changes by +1000; coins from 100 to 98 change by −2.
- The change in velocity, Δv, is a vector: an arrow with a size and a direction. Δv = vₜ − v₀, where v₀ is the initial velocity and vₜ is the final velocity.
- If Δv points the same way as v₀, the object speeds up. If Δv points the opposite way and is shorter than v₀, the object slows down.
- If Δv points the opposite way to v₀ and its arrow is longer than v₀, the object turns around.
- On a straight line: choose a positive direction, give v₀ and vₜ their signs, then compute Δv = vₜ − v₀.
- You can calculate Δv from v₀ and vₜ, but they do not cause it. Something outside the object causes it, such as the brake or the gas pedal.
Step by step
- Choose the positive direction. Take down as positive, the direction of the initial velocity.
- The ball hits the ground moving down at 5 m/s, so v₀ = +5 m/s.
- After the bounce it moves up at 2 m/s. Up is opposite to positive, so vₜ = −2 m/s.
- Compute Δv = vₜ − v₀ = −2 − 5 = −7 m/s.
- The magnitude is 7 m/s. The minus sign means Δv points up, opposite to the positive direction.
- So the change in velocity is 7 m/s upward, not 3 m/s.
Common mistakes
- Wrong: computing initial − final. Right: always compute final − initial, or the sign comes out backwards.
- Wrong: subtracting the two speeds, like 5 − 2 = 3. Right: choose a positive direction first, and give each velocity its sign.
- Wrong: dropping the minus sign, like writing 60 km/h for −60 km/h. Right: a + sign can be dropped, but a − sign cannot.
- Wrong: thinking a bigger velocity means a bigger Δv. A bullet train is fast, but at constant velocity its Δv = 0.
Practice
Question 1. Take right as positive and find Δv for each motorcycle (in km/h). (a) It speeds up from 30 km/h rightward to 100 km/h. (b) It slows down from 80 km/h rightward to 20 km/h rightward. (c) It brakes and turns around, from 40 km/h rightward to 20 km/h the other way.
Show the answer
(a) +70 km/h, (b) −60 km/h, (c) −60 km/h. Right is positive. (a) Δv = 100 − 30 = 70 km/h. (b) Δv = 20 − 80 = −60 km/h. (c) vₜ = −20, so Δv = −20 − 40 = −60 km/h.
Question 2. A particle moves in a straight line. The magnitude of its initial velocity is 2 m/s and the magnitude of its final velocity is 4 m/s. Then ( ) (more than one may be correct)
A. The magnitude of the change in velocity may be 6 m/s
B. The magnitude of the change in velocity may be 4 m/s
C. The change in velocity may point the same way as the initial velocity
D. The change in velocity may point opposite to the initial velocity
Show the answer
A, C and D. Take the initial direction as positive, so v₀ = +2 m/s. If vₜ = +4 m/s, Δv = 4 − 2 = +2 m/s (C). If vₜ = −4 m/s, Δv = −4 − 2 = −6 m/s (A, D). A Δv of magnitude 4 m/s never happens (B is wrong).
Words in English and Chinese
- change in velocity (Δv)
- 速度变化量
- initial velocity
- 初速度
- final velocity
- 末速度
- positive direction
- 正方向
- vector
- 矢量
- scalar
- 标量
- magnitude
- 大小
Sum it up before you move on.
Write this lesson in one line:
- What was the question?
- What is the simple version?
- What would you have got wrong?
Parts of the video (17)
- 0:00Cold open: Δv is 7, not 3
- 0:25Why this lesson: the setup for acceleration
- 1:03What a change means: from initial to final
- 3:21Scalar change: final minus initial
- 5:53"Depends on" vs "can be calculated"
- 9:48"Depends on" goes one way only
- 11:34Change vs initial and final state
- 16:37Velocity change is an arrow
- 21:14Three cases: speed up, slow down, reverse
- 25:31On a line: plus and minus signs
- 29:36Recap: positive direction, then v_t − v_0
- 31:27Practice: compute Δv for three motorcycles
- 34:04True or false: what Δv does not depend on
- 36:07Multiple choice: which statements about Δv are right
- 36:55Example 4: the bouncing ball
- 38:15Only speeds given: two possible answers
- 41:10Summary